How do you solve #10/(p+2)=4/3#?

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Answer 1 · 2016-07-10T14:09:50

#p = 11/2#

Cross multiplication:

#a/b = c/d#

#(a*d)=(b*c)#

So:

#10(3) = 4(p + 2)#

Distribute the numbers over the parenthesis

#30 = 4p + 8#

Solve for #p#

#22 = 4p#

#p = 22/4#

#p = 11/2#