How do you solve # 10 x ^2 − 17 x = 63 #?

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Answer 1 · 2016-02-04T13:52:50

#10x^2-17x=63#

#rarr10x^2-17x-63=0#

Now this is a Quadratic equation (In form #ax^2+bx^2+c=0#)

#x=(-b+-sqrt(b^2-4ac))/(2a)#

In this case #a=10,b=-17,c=-63#

#rarrx=(-(-17)+-sqrt((-17)^2-4(10)(-63)))/(2(10))#

#rarrx=(17+-sqrt(289-(-2520)))/(20)#

#rarrx=(17+-sqrt(289+2520))/20#

#rarrx=(17+-sqrt(2809))/20#

#rarrx=(17+-53)/20#

Now we can assume the two values of #x#:

#rarrx=(17+53)/20,(17-53)/20#

#rarrx=70/20,-36/20#

#rarrx=3 1/2,-1 4/5#