# How do you solve #(10)/(x^2-2x)=4/x=5/(x-2)#?

##### 1 Answer

May 12, 2017

First, we must change the denominators to become the same

( *common denominator* )

The first thing to do is to expand all the denominators, to fully see the components of the fractions.

If we multiply

*multiply all fractions by #(x^2-2x)#*

We are left with