How do you solve $10^x=30$ ?

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Answer 1 · 2015-11-24T14:38:17

$x=log_10 30 ~~ 1.477$

$log_b p = q$ is equivalent to $b^q=p$

Therefore
$10^x=30$ is equivalent to $log_10 30 = x$

$log_10 30$ can be evaluated using a calculator as $~~1.477$

How do you solve 10^x=3010^x=30?