How do you solve #1000e^(-4x)=75#?

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Answer 1 · 2016-12-26T12:07:34

#0.136 (3s.f.)#

#1000e^(-4x)=75#

convert into a logarithmic function:

#1000e^(-4x)=75#

#log_(1000e)(75)=4x#

solve this using a calculator:

#log_(1000e)(75) = 0.54598...#

#4x = 0.54598..#

divide by 4:

#x = (Ans)/4 = 0.136 (3s.f.)#