How do you solve #100x^2 = 121#?

2 Answers
Jul 21, 2016

Answer:

#x = +11/10 or x = -11/10#

Explanation:

The general rule for solving a quadratic equation #(x^2")# is to make it equal to 0.
However this case is the exception because there is no term in #x#.

#100x^2 = 121" make "x^2" the subject"#

#x^2 = 121/100" find the square root"#

#x = +-sqrt(121/100)#

#x = +11/10 or x = -11/10#

We can also follow the usual method to get:

#100x^2 - 121 = 0" factorise"#

#(10x+11)(10x-11)=0#

#x = -11/1 or x = 11/10#

Jul 21, 2016

Answer:

#x=1.1#
#x=-1.1#

Explanation:

#100x^2=121#
OR
#x^2=121/100#
OR
#x=sqrt(121/100)#
OR
#x= 11/10#
#x=1.1#
OR
#x=-11/10#
#x=-1.1#