How do you solve #10b ^ { 2} - 7= - 49#?
1 Answer
Solve algebraically to find that there are no real solutions, but there are complex solutions of the form
Explanation:
We have:
We could add
And divide by
Then take the square root of
Uhh, I'm afraid there is no real solution. We could, however, continue to find complex solutions, by first turning the negative symbol in the root into
Then solve for the root normally. Let's split it into the numerator and the denominator:
Rationalize the denominator:
Now, the plus-or-minus sign there indicates that it could be positive or negative, so we have two solutions:
That's as far as we can go without evaluating the square root.