How do you solve #(10h)/108=5/9#?

2 Answers
Dec 26, 2016

#10/108h=5/9#

Multiply each side by the reciprocal of the coefficient of h. The coefficient of h is #10/108#, so the reciprocal is #108/10#

#h=(5/9)*(108/10)#

#h=(1/1)*(12/2)#

#h=6#

Dec 26, 2016

Answer:

#h = 6#

Explanation:

#(10h)/108 = 5/9" "larr# isolate #h# by #xx 108/10# on both sides

#108/10 xx(10h)/108 = 108/10xx5/9#

#h= cancel108^12/cancel10^2xxcancel5/cancel9#

#h = 6#

Notice that cancelling first avoids ending up with

#h = 540/90#