Step 1) Solve the first equation for #y#:
#10x - 2y = 8#
#(10x - 2y)/color(red)(-2) = 8/color(red)(-2)#
#(10x)/color(red)(-2) + (-2y)/color(red)(-2) = -4#
#-5x + (color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = -4#
#-5x + y = -4#
#color(red)(5x) - 5x + y = color(red)(5x) - 4#
#0 + y = 5x - 4#
#y = 5x - 4#
Step 3) Substitute #(5x - 4)# for #y# in the second equation and solve for #x#:
#4x - 10y = -6# becomes:
#4x - 10(5x - 4) = -6#
#4x - (10 xx 5x) + (-10 xx -4) = -6#
#4x - 50x + 40 = -6#
#(4 - 50)x + 40 = -6#
#-46x + 40 = -6#
#-46x + 40 - color(red)(40) = -6 - color(red)(40)#
#-46x + 0 = -46#
#-46x = -46#
#(-46x)/color(red)(-46) = (-46)/color(red)(-46)#
#(color(red)(cancel(color(black)(-46)))x)/cancel(color(red)(-46)) = 1#
#x = 1#
Step 3) Substitute #1# for #x# in the solution to the first equation at the end of Step 1 and calculate #y#:
#y = 5x - 4# becomes:
#y = (5 xx 1) - 4#
#y = 5 - 4#
#y = 1#
The solution is: #x = 1# and #y = 1# or #(1, 1)#
