# How do you solve 10x² = -5x?

Jan 24, 2017

$x = 0 \mathmr{and} - \frac{1}{2}$
$10 {x}^{2} = - 5 x$
$10 {x}^{2} + 5 x = 0$
$5 x \left(2 x + 1\right) = 0$
For this to be true either $x = 0 \mathmr{and} x = - \frac{1}{2}$