How do you solve #11( 4- 6y ) + 5( 13y + 1) = 9#?

1 Answer

Answer:

#44-66y+65y+5=9#

#49-y=9#

#-y=-40#

#y=40#

Explanation:

The first step you need to do is distribute:

  • #11*4 " "# and #" "11*(-6y)#
  • #5*13y" "# and #" " 5+1#

This gives you:

#44-66y+65y+5=9#

You then need to simplify by joining the related variables:

#44 +5" "# and #" "-66y+65y#

This gives you:

#49-y= 9#

You then need to subtract #49# from both sides:

#-y= -40#

You need to divide both sides by #-1# to get #y# positive. This will give you the answer of

#y = 40#