How do you solve #12+11h= -18-4h#?

1 Answer
Mar 31, 2018

Answer:

#h=-2#

Explanation:

#"collect terms in x on the left side and numeric value on"#
#"the right side"#

#"add 4h to both sides"#

#12+4h+11h=-18cancel(-4h)cancel(+4h)#

#rArr12+15h=-18#

#"subtract 12 from both sides"#

#cancel(12)cancel(-12)+15h=-18-12#

#rArr15h=-30#

#"divide both sides by 15"#

#(cancel(15) h)/cancel(15)=(-30)/15#

#rArrh=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=12+(11xx-2)=12-22=-10#

#"right "=-18-(4xx-2)=-18+8=-10#

#rArrh=-2" is the solution"#