How do you solve #12-2(x-5)=20#?

2 Answers
May 2, 2018

Answer:

Follow explanation

Explanation:

#12-2(x-5) = 20#

#12 - 2x + 10 = 20#

#-2x + 22 = 20#

#-2x = 20 - 22#

#-2x = -2#

#x = (-2)/(-2)#

#x = 1#

This is your answer: #x=1#.

May 2, 2018

Answer:

#x=1#

Explanation:

open the brackets and then simplify the equation first.
#12-2(x-5)=20#
#12-2x+10=20#
#22-2x=20#
#-2x=20-22#
#-2x=-2#
#x=-(-2/2)#
#x=1#
Checking the answer x=1
#12-2(1-5)#
#12-2(-4)#
#12-(-8)#
#12+8=20#