How do you solve 12+24x²-34x=0?

Oct 7, 2017

$x = \left(\frac{2}{3}\right) , \left(\frac{3}{4}\right)$

Explanation:

$24 {x}^{2} - 34 x + 12 = 0$. Dividing the equation by 2,
$12 {x}^{2} - 17 x + 6 = 0$
$12 {x}^{2} - 9 x - 8 x + 6 = 0$
$= 3 x \left(4 x - 3\right) - 2 \left(4 x - 3\right) = 0$
$\left(3 x - 2\right) \left(4 x - 3\right) = 0$
$x = \left(\frac{2}{3}\right) , \left(\frac{3}{4}\right)$

Oct 7, 2017