How do you solve $12+24x²-34x=0$ ?

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Answer 1 · 2017-10-07T18:37:12

$x=(2/3),(3/4)$

$24x^2-34x+12=0$ . Dividing the equation by 2,
$12x^2-17x+6=0$
$12x^2-9x-8x+6=0$
$=3x(4x-3)-2(4x-3)=0$
$(3x-2)(4x-3)=0$
$x=(2/3),(3/4)$

Answer 2 · 2017-10-07T18:41:33

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How do you solve 12+24x²-34x=012+24x²-34x=0?