Solve:
#12(6m+2)=-6(3m+67)#
Divide both sides by #-6#.
#(color(red)cancel(color(black)(12))^2(6m+2))/color(red)cancel(color(black)(-6))^1=(-color(red)cancel(color(black)(6))^1(3m+67))/color(red)cancel(color(black)(-6))^1#
Simplify.
#-2(6m+2)=3m+67#
Expand.
#-12m-4=3m+67#
Add #4# to both sides.
#-12m-4+4=3m+67+4#
Simplify.
#-12m-0=3m+71#
#-12m=3m+71#
Subtract #3m# from both sides.
#-12m-3m=3m-3m+71#
Simplify.
#-15m=0+71#
#-15m=71#
Divide both sides by #-15#.
#(color(red)cancel(color(black)(-15))^1m)/(color(red)cancel(color(black)(-15))^1)=71/(-15)#
Simplify.
#m=-71/15#
We can convert this improper fraction to a mixed number #color(red)(a)color(blue) b/color(green)(c)#. Divide the numerator by the denominator by long division. The whole number quotient is the whole number #(color(red)a)# of the mixed number, the remainder is the numerator #(color(blue)b)#, and the denominator (divisor) stays the same #(color(green)c)#.
#-71-:15=-"4 remainder 11"#
#m=-71/15=-color(red)(4) color(blue)(11)/color(green)(15#
