How do you solve 12(6m+2)=-6(3m+67) 12(6m+2)=6(3m+67)?

1 Answer
Mar 16, 2018

m=-71/15=-4 11/15m=7115=41115

Explanation:

Solve:

12(6m+2)=-6(3m+67)12(6m+2)=6(3m+67)

Divide both sides by -66.

(color(red)cancel(color(black)(12))^2(6m+2))/color(red)cancel(color(black)(-6))^1=(-color(red)cancel(color(black)(6))^1(3m+67))/color(red)cancel(color(black)(-6))^1

Simplify.

-2(6m+2)=3m+67

Expand.

-12m-4=3m+67

Add 4 to both sides.

-12m-4+4=3m+67+4

Simplify.

-12m-0=3m+71

-12m=3m+71

Subtract 3m from both sides.

-12m-3m=3m-3m+71

Simplify.

-15m=0+71

-15m=71

Divide both sides by -15.

(color(red)cancel(color(black)(-15))^1m)/(color(red)cancel(color(black)(-15))^1)=71/(-15)

Simplify.

m=-71/15

We can convert this improper fraction to a mixed number color(red)(a)color(blue) b/color(green)(c). Divide the numerator by the denominator by long division. The whole number quotient is the whole number (color(red)a) of the mixed number, the remainder is the numerator (color(blue)b), and the denominator (divisor) stays the same (color(green)c).

-71-:15=-"4 remainder 11"

m=-71/15=-color(red)(4) color(blue)(11)/color(green)(15