# How do you solve 128/-g<4?

Apr 3, 2018

$g \in \left(- \infty , - 32\right)$
or
g in ]-oo,-32[

#### Explanation:

I'm assuming that you want to find the values of g.

So you start by multiplying both sides by -1 which gives
$\frac{128}{g} > - 4$
then taking the inverse of both sides.
$\frac{g}{128} < - \frac{1}{4}$
then multiplying both sides by 128.
$g < - 32$

so $g \in \left(- \infty , - 32\right)$