Question

How do you solve `128/-g<4`?

Answer 1

`g in (-oo , -32)`
or
`g in ]-oo,-32[`

Explanation:

I'm assuming that you want to find the values of g.

So you start by multiplying both sides by -1 which gives
`128/g > -4`
then taking the inverse of both sides.
`g/128 < -1/4`
then multiplying both sides by 128.
`g< -32`

so `g in (-oo , -32)`