How do you solve #13= \frac { 4- b } { 3}#?

3 Answers
May 29, 2018

Answer:

#b = -35#

Explanation:

As per the question, we have

#13 = (4 - b)/3#

#13# x #3 = (4 - b)/3# x #3# ... [Multiplying 3 on both the sides]

#:.39 = (4 - b)/cancel3# x #cancel3#

#:. 39 = 4 - b#

#:.39 - 4 = 4 - 4 - b# ... [Subtracting 4 from both the sides]

#:.35 = cancel4 cancel-4 - b#

#:. - b = 35#

#:. b = -35#

Hence, the answer.

May 29, 2018

Answer:

#b=-35#

Explanation:

#"multiply both sides by 3"#

#3xx13=cancel(3)xx(4-b)/cancel(3)#

#39=4-b#

#"subtract 4 from both sides"#

#39-4=cancel(4)cancel(-4)-b#

#35=-b" or "b=-35#

#color(blue)"As a check"#

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

#(4-(-35))/3=(4+35)/3=39/3=13#

#b=-35" is the solution"#

May 29, 2018

Answer:

#b=-35#

Explanation:

Multiply by #3#:

#(13xx3)=(4-b)/cancel3#

#rArr 39=4-b#

Bring the #b# to the other side to make is positive:

#b+39=4#

#rArr b=-35#