How do you solve #-14+3e^x=11#?

1 Answer
Jan 26, 2017

#x=ln(25/3)≈2.12#

Explanation:

To solve, we require to isolate the exponential function.

#rArr3e^x=25rArre^x=25/3#

Take the ln ( natural log ) of both sides.

#rArrlne^x=ln(25/3)#

#color(orange)"Reminder "color(red)(bar(ul(|color(white)(2/2)color(black)(logx^n=nlogx;log_b b=1)color(white)(2/2)|))) #

#rArrxcancel(lne)^1=ln(25/3)#

#rArrx=ln(25/3)≈2.12" to 2 decimal places"#