How do you solve #-14+3e^x=11#?
1 Answer
Jan 26, 2017
Explanation:
To solve, we require to isolate the exponential function.
#rArr3e^x=25rArre^x=25/3# Take the ln ( natural log ) of both sides.
#rArrlne^x=ln(25/3)#
#color(orange)"Reminder "color(red)(bar(ul(|color(white)(2/2)color(black)(logx^n=nlogx;log_b b=1)color(white)(2/2)|))) #
#rArrxcancel(lne)^1=ln(25/3)#
#rArrx=ln(25/3)≈2.12" to 2 decimal places"#