How do you solve # 14 ^(7x) = 21#?
1 Answer
May 29, 2016
Explanation:
Take logs of both sides (any base) to get:
#log(21) = log (14^(7x)) = 7x log(14)#
Divide both ends by
#x = log(21)/(7log(14)) ~~ 0.1648#