How do you solve #14e^(3x+2)=560#?

1 Answer
Alan P.
Dec 7, 2015

#x= (ln40-2)/3#

Explanation:

If
#color(white)("XXX")14e^(3x+2) = 560#
then (after dividing both sides by #14#)
#color(white)("XXX")e^(3x+2) = 40#

By taking the natural logarithm of both sides:
#color(white)("XXX")3x+2 = ln40#

#color(white)("XXX")3x = ln40-2#

#color(white)("XXX")x = (ln(40)-2)/3#

Related questions
See all questions in Logarithmic Models
Impact of this question
1612 views around the world
You can reuse this answer
Creative Commons License