# How do you solve  14x^2+3x-2=0?

Jul 8, 2015

The solutions are
color(blue)(x=2/7 , x=-1/2

#### Explanation:

$14 {x}^{2} + 3 x - 2 = 0$

We can first factorise the equation and then find the solutions :

Factorising by splitting the middle term:

$14 {x}^{2} + 3 x - 2 = 0$

$14 {x}^{2} + \textcolor{b l u e}{7 x - 4 x} - 2 = 0$

$7 x \left(2 x + 1\right) - 2 \left(2 x + 1\right) = 0$

color(blue)((7x -2)(2x+1) = 0

Now, equating the factors with zero to obtain the solutions
7x -2 = 0 , color(blue)(x=2/7
2x+1 = 0 ,color(blue)( x =-1/2