How do you solve # 14x^2+3x-2=0#?

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Answer 1 · 2015-07-08T09:27:58

The solutions are
#color(blue)(x=2/7 , x=-1/2#

#14x^2 + 3x -2 = 0#

We can first factorise the equation and then find the solutions :

Factorising by splitting the middle term:

#14x^2 + 3x -2 = 0#

#14x^2 + color(blue)(7x -4x) -2 = 0#

#7x (2x+1) -2 (2x+1) = 0#

#color(blue)((7x -2)(2x+1) = 0#

Now, equating the factors with zero to obtain the solutions
#7x -2 = 0 , color(blue)(x=2/7#
#2x+1 = 0 ,color(blue)( x =-1/2#