# How do you solve -15x^2 + 18x = 0?

Apr 30, 2018

First factor: $0 = - 15 {x}^{2} + 18 x = - 3 x \left(5 x - 6\right)$ so $x = 0$ or $5 x - 6 = 0$, that is, $x = \frac{6}{5.}$

#### Explanation:

Check:

 -15(0)^2 + 18(0) = 0 quad sqrt

$- 15 {\left(\frac{6}{5}\right)}^{2} + 18 \left(\frac{6}{5}\right)$

$= - 15 \left(\frac{36}{25}\right) + \frac{3 \left(36\right)}{5}$

= -{3(36)}/5 + {3(36)}/5 = 0 quad sqrt