# How do you solve #15x^2 + 26x + 8 = 0#?

##### 1 Answer

Jan 4, 2016

#### Answer:

Find a suitable split of the middle term, then factor by grouping to find:

#15x^2+26x+8 = (5x+2)(3x+4)#

#### Explanation:

Find two factors of

The pair

#20 xx 6 = 120#

#20 + 6 = 26#

Then use these to split the middle term and factor by grouping:

#15x^2+26x+8#

#=(15x^2+20x)+(6x+8)#

#=5x(3x+4)+2(3x+4)#

#=(5x+2)(3x+4)#