How do you solve #15x^2=7x+2#?

2 Answers
May 28, 2018

Answer:

#x_1=-1/5# and #x_2=2/3#

Explanation:

#15x^2=7x+2#

#15x^2-7x-2=0#

#15x^2-10x+3x-2=0#

#5x*(3x-2)+3x-2=0#

#(3x-2)*(5x+1)=0#

So #x_1=-1/5# and #x_2=2/3#

May 28, 2018

Answer:

#x_1=2/3# or #x_2=-1/5#

Explanation:

Dividing by #15# we get
#x^2-7/15x-2/15=0#
#x_{1,2}=7/20pmsqrt(49/300+2/15)#
#x_{1,2}=7/30pm13/30#
#x_1=2/3#
#x_2=-1/5#