# How do you solve 15x^2 + 7x=2?

May 26, 2015

y = 15x^2 + 7x - 2 = 0.(1). I use the new Transformation Method for solving quadratic equations. (Google, Yahoo Search)
Transformed equation: x^2 + 7x - 30 = 0 (2)
Factor pairs of a.c = -30 --> (-2, 15)(-3, 10). This sum is 10 -3 = 7 = b.
Then 2 real roots of (2) are: 3 and -10.
Back to (1), the 2 real roots are: $\frac{3}{15} = \frac{1}{5}$ and $- \frac{10}{15} = - \frac{2}{3}$.

This Transformation Method is fast, systematic, no factoring by grouping, no solving binomials.