How do you solve $161= 4x + 3( 3x + 19)$ ?

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Answer 1 · 2017-08-26T01:57:57

See a solution process below: $x = 134/13$

First, expand the terms within the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$161 = 4x + color(red)(3)(3x + 19)$

$161 = 4x + (color(red)(3) xx 3x) + (color(red)(3) xx 19)$

$161 = 4x + 9x + 57$

$161 = (4 + 9)x + 57$

$161 = 13x + 57$

Next, subtract $color(red)(57)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$161 - color(red)(57) = 13x + 57 - color(red)(57)$

$104 = 13x + 0$

$104 = 13x$

Now, divide each side of the equation by $color(red)(13)$ to solve for $x$ while keeping the equation balanced:

$104/color(red)(13) = (13x)/color(red)(13)$

$8 = (color(red)(cancel(color(black)(13)))x)/cancel(color(red)(13))$

$8 = x$

$x = 8$

How do you solve 161= 4x + 3( 3x + 19)161= 4x + 3( 3x + 19)?