How do you solve #16x^2 = 24#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Aviv S. Mar 2, 2018 The answers are #sqrt6/2# and #-sqrt6/2#. Explanation: #16x^2=24# #(16x^2)/16=24/16# #(color(red)cancel(color(black)16)x^2)/color(red)cancel(color(black)16)=24/16# #x^2=24/16# #x^2=3/2# #sqrt(x^2)=sqrt(3/2)# #x=+-sqrt(3/2)# #color(white)x=+-sqrt3/sqrt2# #color(white)x=+-sqrt3/sqrt2color(red)(*sqrt2/sqrt2)# #color(white)x=+-(sqrt3*sqrt2)/(sqrt2*sqrt2)# #color(white)x=+-(sqrt(3*2))/(sqrt(2*2))# #color(white)x=+-sqrt6/sqrt4# #color(white)x=+-sqrt6/2# Those are the two answers. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1700 views around the world You can reuse this answer Creative Commons License