How do you solve #-18- 6k = 6( 1+ 3k )#?

1 Answer
Oct 3, 2017

Answer:

#k=-1#

Explanation:

#"distribute the bracket on the right side"#

#-18-6k=6+18k#

#"collect terms in k on the left side and numeric values"#
#"on the right side"#

#"subtract 18k from both sides"#

#-18-6k-18k=6cancel(+18k)cancel(-18k)#

#rArr-18-24k=6#

#"add 18 to both sides"#

#cancel(-18)cancel(+18)-24k=6+18#

#rArr-24k=24#

#"divide both sides by "-24#

#(cancel(-24) k)/cancel(-24)=24/(-24)#

#rArrk=-1#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=-18+6=-12#

#"right "=6(1-3)=6xx-2=-12#

#rArrk=-1" is the solution"#