Question

How do you solve `-18- 6k = 6( 1+ 3k )`?

Answer 1

`k=-1`

Explanation:

`"distribute the bracket on the right side"`

`-18-6k=6+18k`

`"collect terms in k on the left side and numeric values"`
`"on the right side"`

`"subtract 18k from both sides"`

`-18-6k-18k=6cancel(+18k)cancel(-18k)`

`rArr-18-24k=6`

`"add 18 to both sides"`

`cancel(-18)cancel(+18)-24k=6+18`

`rArr-24k=24`

`"divide both sides by "-24`

`(cancel(-24) k)/cancel(-24)=24/(-24)`

`rArrk=-1`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=-18+6=-12`

`"right "=6(1-3)=6xx-2=-12`

`rArrk=-1" is the solution"`