How do you solve #18\leq x \div 6#?

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Answer 1 · 2017-03-11T19:02:05

See the entire solution process below:

First, rewrite this inequality as:

#18 <= x/6#

Next, multiply each side of the inequality by #color(red)(6)# to solve for #x# while keeping the inequality balanced:

#color(red)(6) xx 18 <= color(red)(6) xx x/6#

#108 <= cancel(color(red)(6)) xx x/color(red)(cancel(color(black)(6)))#

#108 <= x#

To state this solution in term so of #x# we must reverse or "flip" the inequality:

#x >= 108#