How do you solve #19^ { x } = 143#?

1 Answer
Feb 19, 2017

#x≈1.685" to 3 decimal places"#

Explanation:

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx^n=nlogx)color(white)(2/2)|)))#

Take the ln (natural log ) of both sides.

#ln19^x=ln143#

#rArrxln19=ln143#

#rArrx=(ln143)/(ln19)≈1.685#