How do you solve 2[1-3(x+2)]= (-x)?

May 13, 2018

$x = - 2$

Explanation:

2(1−3(x+2))= −x

Let's start with the left side. First we distribute the $- 3$.

$2 \left(1 - 3 x - 6\right) = - x$

We combine the integers.

$2 \left(- 3 x - 5\right) = - x$

Let's distribute the two.

$- 6 x - 10 = - x$

Now we add $6 x$ to both sides to move the $- 6 x$ to the right.

$- 10 = 5 x$

Dividing by five,

$x = - 2$

Check:

 2(1- 3(-2+2))=2= -x quad sqrt