How do you solve #2/10 = 11/x#?

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Answer 1 · 2016-05-24T09:08:53

#x=55#

#2/10=11/x#

Multiplying both sides by #10x# - this is the product of denominators on both sides.

#2/10xx10x=11/x xx10x#

#2/cancel(10)xxcancel(10)x=11/cancelx xx10cancelx#

#2x=110#

now dividing both sides by #2#

#(2x)/2=110/2# or #(cancel(2)x)/((cancel2)1)=55#

or #x=55#