# How do you solve 2(13t-15)+3(t-19)=0?

May 31, 2016

#### Answer:

$t = 3$

#### Explanation:

First distribute the 2 and 3 into their respective binomials. This yields

$\left(26 t - 30\right) + \left(3 t - 57\right) = 0$

Now drop the parentheses and simplify to

$29 t - 87 = 0$

Now you can solve for t by adding 87 to both sides to get

$29 t = 87$

and dividing both sides by 29

$t = \frac{87}{29} = 3$

You can check this answer by plugging it back into the original equation:

$2 \left(13 \left(3\right) - 15\right) + 3 \left(3 - 19\right) = 2 \left(24\right) + 3 \left(- 16\right) = 48 - 48 = 0$