How do you solve #–2(2x – 3) = –6#?
1 Answer
Explanation:
the question:
#–2(2x–3)=–6#
multiply the "internals" of the parentheses by the -2 to remove the parentheses:
#–4x+6=–6#
subtract 6 from both sides to remove it from the left:
#–4x+6-6=–6-6#
the answer so far is:
#–4x=–12#
divide both sides by
#-4x/-4=-12/-4#
the answer:
#x=3#