How do you solve #–2(2x – 3) = –6#?

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Answer 1 · 2015-09-10T22:44:53

#x=3#

the question:

#–2(2x–3)=–6#

multiply the "internals" of the parentheses by the -2 to remove the parentheses:

#–4x+6=–6#

subtract 6 from both sides to remove it from the left:

#–4x+6-6=–6-6#

the answer so far is:

#–4x=–12#

divide both sides by #-4# to remove it from the #x#:

#-4x/-4=-12/-4#

the answer:

#x=3#