How do you solve -2/3(6/5x - 7/10) = 17/20?

Jun 16, 2016

$x = - \frac{23}{48}$

Explanation:

Multiply both sides of the equation by $- \frac{3}{2}$
The equation becomes $\left(\frac{6}{5} x - \frac{7}{10}\right) = \frac{17}{20} \times - \frac{3}{2}$
$\frac{6}{5} x - \frac{7}{10} = - \frac{51}{40}$

Add $\frac{7}{10}$ to both sides
$\frac{6}{5} x = - \frac{51}{40} + \frac{7}{10}$

Find common denominator to add fractions:
$\frac{6}{5} x = - \frac{51}{40} + \frac{28}{40}$

$\frac{6}{5} x = - \frac{23}{40}$

Multiply both sides by reciprocal of $\frac{6}{5}$
$x = - \frac{23}{40} \times \frac{5}{6}$

$x = - \frac{23}{48}$