How do you solve #2(3 - a) - (-2)(a - 3) = - (3a - 2)#?

1 Answer
May 18, 2016

Answer:

#a=2/3#

Explanation:

The first step is to multiply out to get rid of the brackets, remembering that multiplying a negative by a negative gives a positive.
#2(3-a)-(-2)(a-3)=-(3a-2)#

#=6-2a-(-2a+6)=-3a+2#

#=6-2a+2a-6 = -3a+2#

Move all the items to the left hand side, remembering to change the sign.

#=6-2a+2a-6+3a-2=0#

Group the items.

#-2a+2a+3a+6-6-2=0#

#:.3a-2=0#

#3a=2#

#a=2/3#