How do you solve 2(3b-4)=8b-11?

Jun 17, 2015

$b = \frac{3}{2}$

Explanation:

You start multiplying $2$ times the bracket:
$6 b - 8 = 8 b - 11$
Take all the $b s$ on the left and the numbers on the right changing sign when moving them:
$6 b - 8 b = 8 - 11$
$- 2 b = - 3$
take $- 2$ to the right:
$b = \frac{- 3}{-} 2 = \frac{3}{2}$