How do you solve #2/3t< -48#?

1 Answer
Mar 30, 2017

Answer:

See the entire solution process below:

Explanation:

Multiply each side of the inequality by #color(red)(3)/color(blue)(2)# to solve for #t# while keeping the inequality balanced:

#color(red)(3)/color(blue)(2) xx 2/3t < color(red)(3)/color(blue)(2) xx -48#

#cancel(color(red)(3))/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))t < color(red)(3)/color(blue)(2) xx -(2 xx 24)#

#t < color(red)(3)/cancel(color(blue)(2)) xx -(color(blue)(cancel(color(black)(2))) xx 24)#

#t < 3 xx -24#

#t < -72#