How do you solve #2(3u + 7) = -4(3 - 2u) #?

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Answer 1 · 2018-05-18T01:28:01

#u=13#

Solve:

#2(3u+7)=-4(3-2u)#

Apply the distributive property: #a(b+c)=ab+ac#

#2*3u + 2*7=-4*3-4*(-2u)#

#6u+14=-12+8u#

Subtract #8u# from both sides.

#-8u+6u+14=-12#

Simplify #-8u + 6u# to #-2u#.

#-2u+14=-12#

Subtract #14# from both sides.

#-2u=-12-14#

Simplify #12-14# to #-26#.

#-2u=-26#

Divide both sides by #-2#.

#u=(-26)/(-2)#

Simplify #(-26)/(-2)# to #13#.

#u=13#