# How do you solve 2(3x-1)+2(4x+5)=8?

Jan 15, 2017

See the entire solution process below:

#### Explanation:

First, expand the terms in parenthesis by multiplying the by the term outside their respective parenthesis:

$\textcolor{red}{2} \left(3 x - 1\right) + \textcolor{b l u e}{2} \left(4 x + 5\right) = 8$

$\left(\textcolor{red}{2} \times 3 x\right) - \left(\textcolor{red}{2} \times 1\right) + \left(\textcolor{b l u e}{2} \times 4 x\right) + \left(\textcolor{b l u e}{2} \times 5\right) = 8$

$6 x - 2 + 8 x + 10 = 8$

Next, group and combine like terms:

$6 x + 8 x - 2 + 10 = 8$

$14 x + 8 = 8$

Next, subtract $\textcolor{red}{8}$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$14 x + 8 - \textcolor{red}{8} = 8 - \textcolor{red}{8}$

$14 x + 0 = 0$

$14 x = 0$

Now we can divide each side of the equation by $\textcolor{red}{14}$ to solve for $x$ while keeping the equation balanced:

$\frac{14 x}{\textcolor{red}{14}} = \frac{0}{\textcolor{red}{14}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{14}}} x}{\cancel{\textcolor{red}{14}}} = 0$

$x = 0$