Question

How do you solve `2^(3x+1)=3^(x-2)`?

Answer 1

`- log 18/log (3/8)=-2.947`, nearly,

Explanation:

The given equation can be simplified as

`(2^3)^x/3^x=3^(-2)/2^1`.

So, `(3/8)^x=18`.

Equating logarithms and solving,

`x=log 18/log (3/8)`