How do you solve $2^(3x-2)=4^x$ ?

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Answer 1 · 2016-03-29T19:19:48

$x=2$

$2^(3x-2) =4^x$

$color(red)(2)^(3x-2)=color(red)(2)^(2x)$

$"equation has the same base value"$

$3x-2=2x$

$3x-2x=2$

$x=2$

How do you solve 2^(3x-2)=4^x2^(3x-2)=4^x?