How do you solve $2 ^(4x)= 2.7$ ?

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Answer 1 · 2018-04-20T09:51:03

$color(blue)(x=ln(2.7)/(4ln(2))~~0.3582398518)$

By the laws of logarithms:

$log_a(b^c)=clog_a(b)$

$2^(4x)=2.7$

Taking natural logarithms of both sides:

$4xln(2)=ln(2.7)$

Divide by $4ln(2)$ :

$x=ln(2.7)/(4ln(2))~~0.3582398518$

How do you solve 2 ^(4x)= 2.72 ^(4x)= 2.7?