How do you solve #2/5 + 7/8 = y/20 #? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer George C. May 30, 2015 Multiply through by #20# to find: #y = 20*y/20 = 20*(2/5+7/8)# #=(20*2/5)+(20*7/8)# #= (cancel(5)*4*2)/cancel(5) +(cancel(4)*5*7)/(cancel(4)*2)# #= 8 + 35/2# #=16/2+35/2# #=51/2# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1469 views around the world You can reuse this answer Creative Commons License