How do you solve #(2 + 5/x) = (3/x^2)#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer G_Dub Apr 6, 2018 #x=1/2 or x=-3# Explanation: #2+5/x=3/x^2# #2x^2+5x=3# multiply both sides by #x^2# #2x^2+5x-3=0# subtract #3# from both sides #(2x-1)(x+3)=0# factorise trinomial #2x-1=0 or x+3=0# solve quadratic equation #x=1/2 or x=-3 ,(x!=0)# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1349 views around the world You can reuse this answer Creative Commons License