How do you solve $2- 5( x - 5) \leq 7x + 15$ ?

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Answer 1 · 2018-06-05T02:04:15

$x >= 1$

Start with

$2-5(x-5) <= 7x+15$

Distribute the LHS

$2-5x+25 <= 7x+15$

Combine like terms on the LHS

$-5x+27 <= 7x + 15$

Add $5x$ to both sides

$27 <= 12x + 15$

Subtract $15$ from both sides

$12 <= 12x$

Divide both sides by $12$

$1 <= x$

How do you solve 2- 5( x - 5) \leq 7x + 152- 5( x - 5) \leq 7x + 15?