How do you solve #2/9w-1/4=5/6#?

1 Answer
Mar 2, 2017

Sere the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(36)# to eliminate the fractions while keeping the equation balanced:

#color(red)(36)(2/9w - 1/4) = color(red)(36) xx 5/6#

#(color(red)(36) xx 2/9w) - (color(red)(36) xx 1/4) = cancel(color(red)(36))6 xx 5/color(red)(cancel(color(black)(6)))#

#(cancel(color(red)(36))4 xx 2/color(red)(cancel(color(black)(9)))w) - (cancel(color(red)(36))9 xx 1/color(red)cancel(color(black)(4)))) = 30#

#8w - 9 = 30#

Next, add #color(red)(9)# to each side of the equation to isolate the #w# term while keeping the equation balanced:

#8w - 9 + color(red)(9) = 30 + color(red)(9)#

#8w - 0 = 39#

#8w = 39#

Now, divide each side of the equation by #color(red)(8)# to solve for #w# while keeping the equation balanced:

#(8w)/color(red)(8) = 39/color(red)(8)#

#(color(red)(cancel(color(black)(8)))w)/cancel(color(red)(8)) = 39/8#

#w = 39/8#