How do you solve #-2(a+5)=11#?

2 Answers
Apr 1, 2018

Answer:

#a=-21/2#

Explanation:

#-2(a+5)=11#

#-2a-10=11#

#2a=-21#

#a=-21/2#

Apr 1, 2018

Answer:

#a = -10.5#

Explanation:

#-2(a+5) = 11#

You solve this by using the distributive property. That means that you have to multiply the #-2# to everything in the parenthesis:

#-2a-10 = 11#

Now we add #10# to both sides of the equation:
#-2a = 21#

Finally we divide both sides by #-2# to get the value of #a#.
So #a = -10.5#

Hope this helps!