How do you solve #-2(a+5)=11#?

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Answer 1 · 2018-04-01T22:55:24

#a=-21/2#

#-2(a+5)=11#

#-2a-10=11#

#2a=-21#

#a=-21/2#

Answer 2 · 2018-04-01T22:55:46

#a = -10.5#

#-2(a+5) = 11#

You solve this by using the distributive property. That means that you have to multiply the #-2# to everything in the parenthesis:

#-2a-10 = 11#

Now we add #10# to both sides of the equation:
#-2a = 21#

Finally we divide both sides by #-2# to get the value of #a#.
So #a = -10.5#

Hope this helps!