# How do you solve 2(c + 1) - 3c = 3(3 + 2c)?

Mar 13, 2016

Expand the expressions, simplify, then isolate the variable term on one side and the constant on the other to get: $c = 1$

#### Explanation:

Given
$\textcolor{w h i t e}{\text{XXX}} 2 \left(c + 1\right) - 3 c = 3 \left(3 + 2 c\right)$

Expanding
$\textcolor{w h i t e}{\text{XXX}} 2 c + 2 - 3 c = 9 + 6 c$

Simplify
$\textcolor{w h i t e}{\text{XXX}} - c + 2 = 9 + 6 c$

Isolate variable term by subtracting $\left(6 c\right)$ from both sides
$\textcolor{w h i t e}{\text{XXX}} - 7 c + 2 = 9$

Isolate the constant term by subtracting $\left(2\right)$ from both sides
$\textcolor{w h i t e}{\text{XXX}} - 7 c = 7$

Solve for $c$ by dividing both sides by $\left(- 7\right)$
$\textcolor{w h i t e}{\text{XXX}} c = 1$