Question

How do you solve `2(c + 1) - 3c = 3(3 + 2c)`?

Answer 1

Expand the expressions, simplify, then isolate the variable term on one side and the constant on the other to get: `c=1`

Explanation:

Given
`color(white)("XXX")2(c+1)-3c=3(3+2c)`

Expanding
`color(white)("XXX")2c+2-3c=9+6c`

Simplify
`color(white)("XXX")-c+2=9+6c`

Isolate variable term by subtracting `(6c)` from both sides
`color(white)("XXX")-7c+2=9`

Isolate the constant term by subtracting `(2)` from both sides
`color(white)("XXX")-7c=7`

Solve for `c` by dividing both sides by `(-7)`
`color(white)("XXX")c=1`