How do you solve #2( c - 4) + 8= \frac { 1} { 2} ( 6c + 20)#?

2 Answers
Jun 18, 2018

Answer:

#c=-10#

Explanation:

#"distribute brackets on both sides"#

#2c cancel(-8)cancel(+8)=3c+10#

#2c=3c+10#

#"subtract "2c" from both sides"#

#0=c+10#

#"subtract 10 from both sides"#

#-10=crArrc=-10#

Jun 18, 2018

Answer:

#c=-10#

Explanation:

If #2(c-4)+8=1/2(6c+20)#
we have
#4(c-4)+16=6c+20#
#4c-16+16=6c+20#
#4c=16c+20#
Move all the c terms to the left and the constants to the right of the equality sign:
#4c-6c=20#
#-2c=20#
#c=-10#